best lawn mower around $200 image
iciegirl
I have around $500 with me and would like to increase it more to maybe $100 in 1 or 2 months time. What should I do? I'm currently unemployed to take care of family.
Answer
Mowing lawns is a good option, you could buy an old lawn mower for under 100 dollars. Mow about 4 lawns per day at around 25 dollars. You make 100 dollars per day, and if you work three days a week. You are making 300 dollars per week, part time. Therefore you make 1,200 in a months time.
You could wash cars, you could charge 20 dollars to wash a car. You should be able to do about 4 cars in two hours. Charge around 20 dollars and you make around 80 dollars per day. If you want to make more money you could detail cars, you make around 125 dollars on average for detailing cars. But it require more work to do, if you choose this route. The best product to get is optimum no rinse and go on the forum called autopia and autogeek.
Next start an office cleaning or window cleaning business, you can get all of the equipment for under 100 dollars.
Mowing lawns is a good option, you could buy an old lawn mower for under 100 dollars. Mow about 4 lawns per day at around 25 dollars. You make 100 dollars per day, and if you work three days a week. You are making 300 dollars per week, part time. Therefore you make 1,200 in a months time.
You could wash cars, you could charge 20 dollars to wash a car. You should be able to do about 4 cars in two hours. Charge around 20 dollars and you make around 80 dollars per day. If you want to make more money you could detail cars, you make around 125 dollars on average for detailing cars. But it require more work to do, if you choose this route. The best product to get is optimum no rinse and go on the forum called autopia and autogeek.
Next start an office cleaning or window cleaning business, you can get all of the equipment for under 100 dollars.
Can anyone help me with a certain math word problem?
Alexis's L
I am having some trouble with this one word problem. Any help would be kindly appreciated, but please show me how you get the answer.
1. Two people must mow a rectangular lawn measuring 100 feet by 200 feet. The first person agrees to mow 3/4 of the lawn and starts by mowing around the outside. How wide a strip must the person mow on each of the four sides? Also, if the mower has a 24-inch cut, approximate the required number of trips around the lawn.
Answer
Area = w * l = 100ft * 200ft = 20,000ft²
>The first person (A) agrees to mow 3/4 of the lawn
=> A must cut 3/4 * 20,000ft²
>and starts by mowing around the outside. How wide a strip must the person mow on each of the four sides?
Well if the width cut out from each of four sides was x, then the width of the outer shape would be: (200)(100) - (200-2x)(100-2x)
which we require to be 3/4 * (200)(100)
(200)(100) - (200-2x)(100-2x) = 3/4 * (200)(100)
Extracting a factor 4...
(100)(50) - (100-x)(50-x) = 3/4 * (100)(50)
5000 - 5000 +150x -x² = 3750
x² -150x + 3750 = 0
x = [150 ± â(150² - 4(1)(3750))]/ 2(1)
x = [150 ± â(22500 - 15000)]/ 2
x = [150 ± â(7500)]/ 2
x = [150 ± 50â3]/ 2
x = 50 [3 ± â3]/ 2
x = 31.7ft (ignore the other (extraneous) solution)
Also, if the mower has a 24-inch cut, approximate the required number of trips around the lawn.
31.7ft / 2ft â 16 trips [SOLUTION]
________________________
The rest isn't necessary, but the exact area if A cuts a decreasing spiral, with a cut-width c=2ft:
Assuming A starts horizontally, first cut is 200ft*2ft
Next cut is vertical, with area: (100-2)ft * 2ft
Next cut is horizontal, with area: (200-2)ft * 2ft
Next cut is vertical, with area: (100-2(2))ft * 2ft
etc.
So the area of the ith horizontal cut is
A(i) = (200-2(i))*2 = 4(100-i)
starting numbering from i=0.
and area of the ith vertical cut is
A(i) = (100-2(i))*2 = 4(50-i)
starting numbering from i=1 (! not 0, different to horizontal).
So the area of both the ith horizontal+vertical cuts is:
A(i) = 4(150-i)
Noting the special case A(0) = 400
then the total area cut after the nth cut is:
S(n) = A(0)+ Σ_i=1_i=n A(i)
S(n) = 400+ Σ_i=1_i=n 4(150-i)
= 400+ (4)(150)n - 4 (n)(n+1)/2
= 400+ 600n - 2n² -2n
= 400+ 598n - 2n²
and you could get the exact solution by solving
S(n) = 3/4 * (200)(100)
etc.
Area = w * l = 100ft * 200ft = 20,000ft²
>The first person (A) agrees to mow 3/4 of the lawn
=> A must cut 3/4 * 20,000ft²
>and starts by mowing around the outside. How wide a strip must the person mow on each of the four sides?
Well if the width cut out from each of four sides was x, then the width of the outer shape would be: (200)(100) - (200-2x)(100-2x)
which we require to be 3/4 * (200)(100)
(200)(100) - (200-2x)(100-2x) = 3/4 * (200)(100)
Extracting a factor 4...
(100)(50) - (100-x)(50-x) = 3/4 * (100)(50)
5000 - 5000 +150x -x² = 3750
x² -150x + 3750 = 0
x = [150 ± â(150² - 4(1)(3750))]/ 2(1)
x = [150 ± â(22500 - 15000)]/ 2
x = [150 ± â(7500)]/ 2
x = [150 ± 50â3]/ 2
x = 50 [3 ± â3]/ 2
x = 31.7ft (ignore the other (extraneous) solution)
Also, if the mower has a 24-inch cut, approximate the required number of trips around the lawn.
31.7ft / 2ft â 16 trips [SOLUTION]
________________________
The rest isn't necessary, but the exact area if A cuts a decreasing spiral, with a cut-width c=2ft:
Assuming A starts horizontally, first cut is 200ft*2ft
Next cut is vertical, with area: (100-2)ft * 2ft
Next cut is horizontal, with area: (200-2)ft * 2ft
Next cut is vertical, with area: (100-2(2))ft * 2ft
etc.
So the area of the ith horizontal cut is
A(i) = (200-2(i))*2 = 4(100-i)
starting numbering from i=0.
and area of the ith vertical cut is
A(i) = (100-2(i))*2 = 4(50-i)
starting numbering from i=1 (! not 0, different to horizontal).
So the area of both the ith horizontal+vertical cuts is:
A(i) = 4(150-i)
Noting the special case A(0) = 400
then the total area cut after the nth cut is:
S(n) = A(0)+ Σ_i=1_i=n A(i)
S(n) = 400+ Σ_i=1_i=n 4(150-i)
= 400+ (4)(150)n - 4 (n)(n+1)/2
= 400+ 600n - 2n² -2n
= 400+ 598n - 2n²
and you could get the exact solution by solving
S(n) = 3/4 * (200)(100)
etc.
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