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The engine of the Honda lawn mower starts and runs perfect but it has to be pushed. It started doing this last year but now it's terrible. The cable was out to the end of the adjustment so I replaced it and that didn't help one bit. What else could it be?
It's got a belt that seems OK. It could be stretched, but how do you tell. If it's the transmission, I'll junk it.
Answer
I agree with the first poster, your belt is off. Turn the mower over and you will see that between the blades and the motor is a pulley. That pulley should have a belt around it that travels to another pulley between the rear wheels.
The 'clutch' so to speak is basically a lever that pushes or pulls the belt tighter, the tighter the belt, the faster the wheels turn.
Between the rear wheels is a small box that transfers power from the pulley on top of it to the axle. It is possible that this box (called a trans axle) is broken and can no longer transfer the power. If the belt moves the pulley on top of the trans axle and it still does not go, that is the issue.
I agree with the first poster, your belt is off. Turn the mower over and you will see that between the blades and the motor is a pulley. That pulley should have a belt around it that travels to another pulley between the rear wheels.
The 'clutch' so to speak is basically a lever that pushes or pulls the belt tighter, the tighter the belt, the faster the wheels turn.
Between the rear wheels is a small box that transfers power from the pulley on top of it to the axle. It is possible that this box (called a trans axle) is broken and can no longer transfer the power. If the belt moves the pulley on top of the trans axle and it still does not go, that is the issue.
Why is it easier to pull a lawn mower or a hand truck than to push it?
Mike R
Physics related?
Answer
Why is it easier to pull a lawn mower or a hand truck than to push it?
Physics related?
When I push a lawn mower, the lawn mower is in front of me. I have BOTH ARMS bent at a 90º angle at the elbow. My shoulder muscles are exerting the force. This force times the length of my upper arm equals the torque that produces the horizontal force that moves the lawn mower. The perpendicular distance from my shoulder joint to my hands = 25 cm.
Let F = horizontal force required to overcome friction and push the lawn mower at a constant velocity.
Total torque required = F * 0.25 Nm
So the shoulder muscles on the left side of my body have to produce ½ * F * 0.25 = F * 0.125 Nm
When I pull a lawn mower, the lawn mower is behind me. I have ONE ARM bent behind me at a 150º angle at the elbow. Only ONE ARMâS shoulder muscle is exerting the force. The distance from my shoulder joint to my hand = 0.25 * cos 30º
Torque required by ONE ARMâS shoulder muscle = F * 0.25 * cos 30º = F * 0.217 Nm
If I push the lawn mower or a hand truck, one shoulder muscle has to produce a torque equal to 0.125 times the horizontal force required to overcome friction and push the lawn mower at a constant velocity.
If I pull the lawn mower or a hand truck, one shoulder muscle has to produce a torque equal to 0.217 times the horizontal force required to overcome friction and push the lawn mower at a constant velocity
Why is it easier to pull a lawn mower or a hand truck than to push it?
Physics related?
When I push a lawn mower, the lawn mower is in front of me. I have BOTH ARMS bent at a 90º angle at the elbow. My shoulder muscles are exerting the force. This force times the length of my upper arm equals the torque that produces the horizontal force that moves the lawn mower. The perpendicular distance from my shoulder joint to my hands = 25 cm.
Let F = horizontal force required to overcome friction and push the lawn mower at a constant velocity.
Total torque required = F * 0.25 Nm
So the shoulder muscles on the left side of my body have to produce ½ * F * 0.25 = F * 0.125 Nm
When I pull a lawn mower, the lawn mower is behind me. I have ONE ARM bent behind me at a 150º angle at the elbow. Only ONE ARMâS shoulder muscle is exerting the force. The distance from my shoulder joint to my hand = 0.25 * cos 30º
Torque required by ONE ARMâS shoulder muscle = F * 0.25 * cos 30º = F * 0.217 Nm
If I push the lawn mower or a hand truck, one shoulder muscle has to produce a torque equal to 0.125 times the horizontal force required to overcome friction and push the lawn mower at a constant velocity.
If I pull the lawn mower or a hand truck, one shoulder muscle has to produce a torque equal to 0.217 times the horizontal force required to overcome friction and push the lawn mower at a constant velocity
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